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4.If the sum of four consecutive odd numbers is 56, find the four numbers.​

Answer»

Given :

  • the SUM of four consecutive odd numbers is 56

To FIND :

  • the four numbers

Solution :

⇒ Let the consecutive odd numbers be :

  • 2x + 1
  • 2x + 3
  • 2x + 5
  • 2x + 7

⇒ Now, let's find.

= (2x + 1) + (2x + 3) + (2x + 5) + (2x + 7) = 56

= 2x + 1 + 2x + 3 + 2x + 5 + 2x + 7 = 56

= (2x + 2x + 2x + 2x) + (1 + 3 + 5 + 7) = 56

= (8X) + (16) = 56

= 8x + 16 = 56

= 8x = 56 - 16

= 8x = 40

= x = 40/8

= x = 5

⇒ Let's find the numbers.

→ 2x + 1

= 2 × 5 + 1

= 10 + 1 = 11

→ 2x + 3

= 2 × 5 + 3

= 10 + 3 = 13

→ 2x + 5

= 2 × 5 + 5

= 10 + 5 = 15

→ 2x + 7

= 2 × 5 + 7

= 10 + 7 = 17

  • Therefore, the four numbers are 11, 13, 15, and 17.


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