1.

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ……

Answer»

`0.004`
`0.008`
`0.012`
`0.016`

SOLUTION :EXPLANATION :
APPLY the reaction : `M_(1)V_(1)=M_(2)V_(2)`
GIVEN : `M_(1)=0.02 M, V_(1)=4 L, M_(2)=? V_(2)=5L`
Therefore, `0.02xx4L=M_(2)XX 5L`
`M_(2)=0.08//5=0.016 M`


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