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4 muF and 6 muF capacitors are joined in series and 500 V are applied between the outer plates of the system. What is the charge on each plate '? |
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Answer» `1.2xx10^(-3) C ` ` C = (4xx6)/(4+6) ` `= (24)/(10)` `= 2.4 mu F ` Total CHARGE on CAPACITOR is Q= CV `= 2.4 xx10^(-6) xx500 ` `= 12 xx10^(-4) = 1.2 xx10^(-3) C ` `:.` Charge on each plate as series connection is `= 1.2 xx10^(-3) ` C |
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