1.

(4)SOFor hydrogen gas C,-C,-a and for oxygen gas CC, 〒 b. ,So the relation between a and b is given by:-(Where Cp, Cy are molar sp. heat at const. pressureand const. volume)(1) a = 16b41.(2) b= 16a(4) a b(3) a4b

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Cp and Cv are specific heats per gram

a=Cp - Cv = R/2{for hydrogen gas} as[R is per mole of H₂ i.e. 2grams]hope you getting it,,its not always cp-cv=R its only for ideal cases

similarly

b=Cp - Cv = R/28{for nitrogen gas} as[R is per mole of N₂ i.e. 28 grams]

from above eqns.

a=R/2 →2a=R

substituting value in eqn 2

b=2a/28

→14b=a

so,,, a=14b



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