4. The sides of a triangle are 12 cm and 15 cm. The lengthof the altit

1.	4. The sides of a triangle are 12 cm and 15 cm. The lengthof the altitude on the shorter of these two sides is 10 cm.Find (a) the area of the triangles, (b) the altitude on theother side.with adiacent sides 24 cm and
Answer» Answer: Hope it helps :) Step-by-step EXPLANATION: so I GOT some changes please don't mind it and USE the formula Given, SIDES of triangle 5 cm, 12 cm, 13 cm. Now semi perimeter, s= = 2 sum of the sides of triangle = 2 5+12+13 =15 cm Using heron's formula, AREA of triangle= s(s−a)(s−b)(s−c) = 15(15−5)(15−12)(15−13) = 15×10×3×2 =30cm 2 Using altitude, area of triangle = 2 1 × base × altitude =30cm 2 = 2 1 ×13× altitude =30 = altitude = 13 30×2 =4.61 cm So, altitude corresponding to largest side is 4.61 cm.

4. The sides of a triangle are 12 cm and 15 cm. The lengthof the altitude on the shorter of these two sides is 10 cm.Find (a) the area of the triangles, (b) the altitude on theother side.with adiacent sides 24 cm and

Answer»

Answer:

Hope it helps :)

Step-by-step EXPLANATION:

so I GOT some changes please don't mind it and USE the formula

Given, SIDES of triangle 5 cm, 12 cm, 13 cm.

Now semi perimeter, s= =

sum of the sides of triangle

5+12+13

=15 cm

Using heron's formula, AREA of triangle=

s(s−a)(s−b)(s−c)

15(15−5)(15−12)(15−13)

15×10×3×2

=30cm

Using altitude, area of triangle =

× base × altitude =30cm

×13× altitude =30

= altitude =

30×2

=4.61 cm

So, altitude corresponding to largest side is 4.61 cm.