4. Two objects of masses 100 g and 200 g are moving along the same lin

1.	4. Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 ms-1and 1 ms-1. respectively
Answer» Answer: EXPLANATION: Answer: 1.165 m/s Explanation: Mass of first objects, m₁= 100 g = 0.1 kg Mass of SECOND object, m₂ = 200 g = 0.2 kg Velocity of m, before collision, v₁= 2 m/s Velocity of m₂ before collision, V₂ = 1 m/s Velocity of m₁ after collision, V3 = 1.67 m/s after collision = V4 Velocity of m2 According to the law of conservation of momentum: Total momentum before collision = Total momentum after collision + m₂V2 = M₁V3+ M₂V4 → 0.1 * 2 + 0.21 = 0.1 1.67 + 0.2 * V4 → 0.4 0.67 + 0.2 * V4 → V4 = 1.165 m/s Hence, the velocity of the second object becomes 1.165 m/s after the collision.

4. Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 ms-1and 1 ms-1. respectively

Answer»

Answer:

EXPLANATION:

Answer:

1.165 m/s

Explanation:

Mass of first objects, m₁= 100 g = 0.1 kg Mass of SECOND object, m₂ = 200 g = 0.2 kg

Velocity of m, before collision, v₁= 2 m/s

Velocity of m₂ before collision, V₂ = 1 m/s Velocity of m₁ after collision, V3 = 1.67 m/s

after collision = V4

Velocity of m2 According to the law of conservation of momentum:

Total momentum before collision = Total momentum after collision

+ m₂V2 = M₁V3+ M₂V4

→ 0.1 * 2 + 0.2*1 = 0.1 * 1.67 + 0.2 * V4

→ 0.4 0.67 + 0.2 * V4

→ V4 = 1.165 m/s

Hence, the velocity of the second object becomes 1.165 m/s after the collision.

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