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8- A girl of mass 35 kg site on trolley of mas 5kg.initial velocity of trolley is im/s Come to rest after travelling 16m.find work done on trolley.come to meet after thavelling 16 m(a) work done ou trolley(b) work done by girl |
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Answer» Answer: Given: Mass of girl = 35 kg Mass of TROLLEY = 5 kg Total mass, m = (35 + 5) = 40 kg u = 4 m/s v = 0 s = 16 m By equation, v 2 = u 2 + 2as 0 = (4)2 + 2a (16) 32a = –16 a = –0.5 m/s2 Force exerted on trolley, F = ma = 40 × 0.5 = 20 N
Work DONE on trolley W = FS = 20 N X 16 m = 320 J Work done by the girl, W = FS = mass of girl × retardation × S = 35 × 0.5 × 16 = 280 J |
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