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8- A girl of mass 35 kg site on trolley of mas 5kg.initial velocity of trolley is im/s Come to rest after travelling 16m.find work done on trolley.come to meet after thavelling 16 m(a) work done ou trolley(b) work done by girl

Answer»

Answer:

Given:

Mass of girl = 35 kg

Mass of TROLLEY = 5 kg

Total mass, m = (35 + 5) = 40 kg

u = 4 m/s

v = 0

s = 16 m

By equation,

v 2 = u 2 + 2as

0 = (4)2 + 2a (16)

32a = –16

a = –0.5 m/s2

Force exerted on trolley,

F = ma

= 40 × 0.5 = 20 N

Work DONE on trolley W = FS = 20 N X 16 m

= 320 J

Work done by the girl, W = FS

= mass of girl × retardation × S

= 35 × 0.5 × 16

= 280 J



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