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`4 x^2-2 x+a=0,` has two roots lies in`(-1,1)` then ? |
Answer» Let `f(x)=4x^(2)-2x+a` as both roots of the equation `f(x)=0` are lie between `(-1,1)` we can take `D ge0` `af(-1)gt0,af(1)gt0` and `-1lt1/4lt1` (i) Consider `Dge0` `(-2)^(2)-4.4.age0impliesale1/4`…….i (ii) Consider `af(-1)gt0` `4(4+2+a)gt0` `impliesage-6impliesa epsilon(-6,oo)`.............ii (iii) Consider `af(1)gt0` `4(4-2+a)gt0impliesagt-2` `impliesa epsilon(-2,oo)`.........iii Hence the values of `a` satisfying Eqs. (i), (ii) and (iii) at the same time are `a epsilon(-2,1/4]` |
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