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4.x + 2y -5 505.7x - 4y < 146.x + 8y+10 > 0solve graphically |
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Answer» Given lines4x−7y+10=0−−−−(1)x+y−5=0−−−−(2)7x+4y−15=0−−−−(3)On solving EQ (1) and (3)7x+4( 74x+10 )−15=049x+16x+40−105=065x=65⇒x=1From eq (1)4−7y=−10−7y=−14y=2Point of intersection is (1,2)Here Equation (1) and (3) are perpendicular So the LINES formed RIGHT angle triangle HENCE the orthocentre of Right angle triangle is the point at which 90 0 angle is formed Hence (1,2) is orthocentre |
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