4(x²+xy) tu-xy when x=5 and 4= 3 – InterviewSolution

1.

4(x²+xy) tu-xy when x=5 and 4= 3

Answer»

Step-by-step explanation:

4(x^2+xy)tu-xy=0

4(5^2+5(3))tu-5(3)=0

4(25+15)tu-15=0

4(40)tu-15=0

160tu-15=0

160tu=15

Tu=15/160

Tu=3/32

Hi, I hope this is correct, if it is wrong I'm so sorry

I TRIED my level best

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