1.

4 years ago Seema's age was 3 times the age ofher son. The sum of their ages 4 years ago was 48 years. Find their present ages.​

Answer»

Let age of SON = x

seemas age = 3x

4 years AGO,

son = x-4

seema = 3x - 4

given

x-4 + 3x-4 = 48

4x - 8 = 48

4x = 56

x = 14

age of son = 14

age of seema = 42



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