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40 1 mol of KClO3(s) gives 80%yield of KCl(s)+O2(g).if 2 mol of KClO3 were used in above reaction ,then volume of oxygen form at NTP will be 22.4L 53.76L 67.2L 13.4L

Answer» 40 1 mol of KClO3(s) gives 80%yield of KCl(s)+O2(g).if 2 mol of KClO3 were used in above reaction ,then volume of oxygen form at NTP will be 22.4L 53.76L 67.2L 13.4L


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