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40% by weight solution will contain how much mass of the solute in 1 solution, density of the solution is 1.2 g/mL |
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Answer» 480 G when M = mol. Weight of the solute Molarity `=(40xx1.2xx10)/(Mxx1000)`.......(i) Molarity `=("weight of the solute / M")/("VOLUME of solution (in litre)")`..........(ii) From Eqs. (i) and (ii) `("Weight of solute")/(M xx 1000)=(40xx1.2xx10)/(M xx 1000)` Weight of solute = 480 g. |
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