40. How many carbon atoms are present in 0.35 mol of C6H1206-(A) 6.023 – InterviewSolution

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40. How many carbon atoms are present in 0.35 mol of C6H1206-(A) 6.023 x 1025 carbon atoms (B) 1.26 x 1023 carbon atoms(C71.26 x 1024 carbon atoms (D) 6.023 x 1024 carbon atoms

Answer»

answer c is correct hai

6×0.35×6.023×10^23=12.64×10^23=1.26×10^23

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