1.

40 mg of pure sodium hydroxide is dissolved in 10 litres of distilled water. The pH of the solution is

Answer»

`9.0`
10
11
12

Solution :`M = ("Solute in 1 litre solution")/("Molecular weight of solute")`
`= (40 xx 10^(-3))/(40)xx (1)/(10) = 10^(-4) M`
`POH = LOG 10. (1)/([OH^(-)]) = log 10. (1)/(10^(-4)) = 4`
`PH + pOH = 14, pH + 4 = 14 rArr pH = 10`.


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