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`400 c c` volume of gas having `gamma=5/2` is suddenly compressed to `100 c c`. If the initial pressure is `P`, the final pressure will beA. `P//32`B. `8P`C. `32P`D. `16P` |
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Answer» Correct Answer - C Here, `V_(1)=400 c c, V_(2)= 100 c c, gamma=5/2, P_(1)=P` `P_(2)=?` for adiabatic change, `P_(2)V_(2)^(gamma)=P_(1)V_(1)^(gamma)` `:. P_(2)=P_(1)((V_(1))/(V_(2)))^(gamma)` `P_(2)=P ((400)/(100))^(5//2)` `= Pxx4xx4xxsqrt(4)=32P` |
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