1.

400 cm^(3) of water is added to 6% of 600 g (molar mass =36) of a solute. The molarity contain 20 millimoles of the solute is

Answer»

3
1.5
0.25
1

Solution :6% of 600 gm = `W_(2) = 36g`
`C=W/("Molar mass" xx V(DM^(3)))`
`C=36/(36 xx 0.4)=1/(0.4)=0.25`


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