1.

45 g of ethylene glycol (C_(2)H_(6)O_(2)) is mixed with 650 g of water. The freezing point depression (in K) will be (K_(f)"for water "=1.86 "K kg mol"^(-1)).

Answer»

Solution :Molality of solution (m)
`=("No of moles of "C_(2)H_(6)O_(2))/("Mass of water in kg")`
`=(((45G))/((62" G mol"^(-1))))/(6.65kg)=((0.73 mol))/((0.65kg))=1.12"mol kg"^(-1)`
`DeltaT_(f)=K_(f)xxm=(1.86" K kg mol"^(-1))xx(1.12 "mol kg"^(-1))`
`=2.08 K~~2K.`


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