1.

45 grams of ethylene glycol (C_(2)H_(6)O_(2)) is mixed with 600 grams of water. What is the depression in freezing point (K_(f) for water = 1.86 kg "mole"^(-1)) (C = 12, O = 16, H = 1 g/mol).

Answer»

2.25 K
22.5 K
3.25 K
32.5 K

Solution :M.F `= C_(2)H_(6)O_(2)`
M.wt `= 2(12)+6(1)+2(16)`
`= 62 g mol^(-1)=M_(2)`
Weight of ETHYLENE glycol = 45 g `= W_(2)`
Weight of solvent (water = 600 g `= W_(1)`
`K_(f)` (water) = 1.86 kg `mol^(-1)`
`Delta T = K_(f)m`
`= (K_(f)XX W_(2)xx1000)/(M_(2)xx W_(1))`
`= (1.86xx 45" gram" xx 1000)/(62 g mol^(-1)xx 600 " gram")`
= 2.25 K


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