1.

450 mg of glucose is dissolved in 100 g of solvent. What is the molality of the solution ?A. `0.0025` mB. `0.025` mC. `0.25`mD. 2.5 m

Answer» Correct Answer - B
Molality = `("moles of solute" xx 1000)/("weight of solvent (in g)")`
or
`= ("weight of solute" xx 100)/("mol., wt of solute" xx "weight of solvent (in g)")`
`= (450 xx 10^(-3) xx 1000)/(180 xx 100)`
`[because` Mol. Mass of glucose = 180]
`= 0.025` m


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