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`Ce^(4+)` is stable . This is because ofA. half-filled d-orbitalsB. all paired electrons in d-orbitalsC. empty orbitalD. fully filled d-orbital |
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Answer» Correct Answer - C The electronic configuration of Ce is `Ce_(58) = [Xe] 4 f^(1) 5d^(1) 6s^(2)` (predicted) or = `[Xe] 4f^(2) 5d^(0) 6s^(2) `(observed) `Ce^(4+) = [Xe] 4 f^(0) 5d^(0) 6s^(0)` Since , in +4 oxidation state , all (ie, 4f , 5d and 6s) orbitals are empty and Ce gains the stable configuration of nearest inert gas , `Ce^(4+)` is most stable . |
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