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The solution of the differential equation `y (1 + log x) (dx)/(dy) - x log x = 0` isA. y log x = y + cB. x log x = ycC. y (1 + log x) = cD. logx - y = c |
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Answer» Correct Answer - B Given differential equation is `y (1 + log x ) (dx)/(dy) - x log x = 0` `implies int (1 + log x)/(x log x ) dx = int (dy)/(y)` `implies int (1)/(x log x ) dx + int (1)/(x) dx = int (1)/(y) dy` `implies log (log x) + log x = log y + log c ` `implies x log x= y c` |
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