46a7b2 is a six-digit number where ‘a’ and ‘b’ are digits in thousands and tens place. If this number is divisible by 9, what should be the least possible value of a + b? Please explain.

46a7b2 is a six-digit number where ‘a’ and ‘b’ are digits in t

1.	46a7b2 is a six-digit number where ‘a’ and ‘b’ are digits in thousands and tens place. If this number is divisible by 9, what should be the least possible value of a + b? Please explain.
Answer» -STEP EXPLANATION:The VALUE will be 8 MEANS a=7 b=1

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46a7b2 is a six-digit number where ‘a’ and ‘b’ are digits in thousands and tens place. If this number is divisible by 9, what should be the least possible value of a + b? Please explain.

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