1.

47. Calculate the wave length of the secondline of Lyman series in hydrogen spectra!(Given R, = 1.09737 cm-"). (t j 56.

Answer»

1/ λ = R[1/n₁² - 1/n₂²]

For second line of Lyman seriesn₁ = 1 and n₂ = 3

1/λ = R[1/1² - 1/3²]= 8R/9

λ = 9 / (8R)= 9 / (8 × 1.097 × 10^7 m^1)= 102.5 nm

∴ Wavelength of second line of Lyman series is 102.5 nm



Discussion

No Comment Found

Related InterviewSolutions