InterviewSolution
Saved Bookmarks
| 1. |
47. Calculate the wave length of the secondline of Lyman series in hydrogen spectra!(Given R, = 1.09737 cm-"). (t j 56. |
|
Answer» 1/ λ = R[1/n₁² - 1/n₂²] For second line of Lyman seriesn₁ = 1 and n₂ = 3 1/λ = R[1/1² - 1/3²]= 8R/9 λ = 9 / (8R)= 9 / (8 × 1.097 × 10^7 m^1)= 102.5 nm ∴ Wavelength of second line of Lyman series is 102.5 nm |
|