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47) the distance between the points (4, y) and (1, 0) is 5 then y= |
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Answer» Distance between the GIVEN POINT= (x 2 −x 1 ) 2 +(y 2 −y 1 ) 2 Here x 1 =y,y 1 =y and x 2 =1,y 2 =0Distance=5∴5= (1−4) 2 +(0−y) 2 ⇒5= 3 2 +y 2 ⇒25=9+y 2 ⇒y 2 =9−25⇒−y 2 =−16⇒y=±4Answered By |
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