1.

4a square_4b square + 4a +1 factorize it

Answer»

−9b2+(2a+1)2-9b2+(2a+1)2

Rewrite 9b29b2 as (3b)2(3b)2.

−(3b)2+(2a+1)2-(3b)2+(2a+1)2

Reorder −(3b)2-(3b)2 and (2a+1)2(2a+1)2.

(2a+1)2−(3b)2(2a+1)2-(3b)2

Since both terms are perfect squares, factor USING the DIFFERENCE of squaresformula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=2a+1a=2a+1 and b=3bb=3b.

(2a+1+3b)(2a+1−(3b))(2a+1+3b)(2a+1-(3b))

MULTIPLY 33 by −1-1 to get −3-3.

(2a+1+3b)(2a+1−3b)

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Hope it helps you


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