1.

4Cu+ 10HNO_(3) to Cu(NO_(3))_(2) + X + H_(2)O Mention the substance 'X'

Answer»

`NO_(2)`
`N_(2)O`
NO
`N_(2)O_(3)`

SOLUTION :`4Cu_(g) + underset("dilute")(10HNO_(3))(g) to 4Cu(NO_(3))_(2)(aq) + 5H_(2)O (L) + N_(2X) O_(g)`


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