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4HBr+O_(2)to2H_(2)O+2Br_(2). The molecularity of the reaction appears as 5, but experimentally, it is 2. Explain. |
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Answer» Solution :The mechanism of OXIDATION reaction of HBr is given in three STEPS. `HBr+O_(2) to HOOBr, HOOBr+HBr to 2HOBr HOBr+HBr to H_(2)O+Br_(2)` MOLECULARITY of each step is `2`. The overall molecularity of the slowest step `(1st)` is `2` |
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