1.

4HBr+O_(2)to2H_(2)O+2Br_(2). The molecularity of the reaction appears as 5, but experimentally, it is 2. Explain.

Answer»

Solution :The mechanism of OXIDATION reaction of HBr is given in three STEPS.
`HBr+O_(2) to HOOBr, HOOBr+HBr to 2HOBr HOBr+HBr to H_(2)O+Br_(2)`
MOLECULARITY of each step is `2`.
The overall molecularity of the slowest step `(1st)` is `2`


Discussion

No Comment Found