`4S(s)+60to4SO_(3)(g),DeltaH` f or this reaction is - 1583.2 kJ . The enthalpy of formation of sulphur trioxide is -A. `-395.8 kJ`B. `395 .8 kJ`C. `49.5 kJ`D. `595.5kJ`

`4S(s)+60to4SO_(3)(g),DeltaH` f or this reaction is - 1583.2 kJ . The

1.	`4S(s)+60to4SO_(3)(g),DeltaH` f or this reaction is - 1583.2 kJ . The enthalpy of formation of sulphur trioxide is -A. `-395.8 kJ`B. `395 .8 kJ`C. `49.5 kJ`D. `595.5kJ`
Answer» Correct Answer - 1

`4S(s)+60to4SO_(3)(g),DeltaH` f or this reaction is - 1583.2 kJ . The enthalpy of formation of sulphur trioxide is -A. `-395.8 kJ`B. `395 .8 kJ`C. `49.5 kJ`D. `595.5kJ`
Enthalpy change for reaction `1//2H_(2)(g)+1//2Cl_(2)(g)toHCl(g)` is called :-A. Enthalpy of combustionB. Enthalpy of solutionC. Enthalpy of formationD. Enthalpy of fusion
Change in enthalpy for reaction `2H_(2)O_(2)(l)rarr2H_(2)O(l)+O_(2)(g)` if heat of formation of `H_(2)O_(2)(l)` and `H_(2)O(l)` are `-188` and `-286KJ//mol` respectively isA. `-196 kJ//mol`B. `+196 kJ//mol`C. `+948 kJ//mol`D. `-948 kJ//mol`
If a `298K` the bond energies of `C-H,C-C,C=C` and `H-H` bonds are respectivly `414, 347, 615KJmol^(-1)` , the vlaue of enthalpy change for the reaction `H_(2)C=CH_(2)(g)+H_(2)(g)+H_(2)(g)rarrH_(3)C-CH_(3)(g)` at `298K` will beA. `+125 kJ`B. `-125 kJ`C. `+250 kJ`D. `-250kJ`
Molar heat of vapourisation of a liquid is `6kJ"mol"^(1)` . If the entopy change is 16 `J"mol"^(-1)K^(-1)`, the boiling point of the liquid is :-A. `375^(@)C`B. 375 KC. 273 KD. `102^(@)C`
The work done during the expanision of a gas from a volume of `4 dm^(3)` to `6 dm^(3)` against a constant external pressure of 3 atm is (1 L atm = 101.32 J)A. `+304 J`B. `-304 J`C. `-6 J`D. `-608 J`
The bond dissociation energy of gaseous `H_(2),Cl_(2)` and `HCl` are `104,58` and `103 kcal mol^(-1)` respecitvely. Calculate the enthalpy of formation for `HCl` gas.A. `+44 kCal`B. `+22 k Cal`C. `-22 kCal`D. `-44 kCal`