1.

4x + 1 over 3y2What is the value of the expression above when x = 2 and y = 3? You must show all work and calculations to receive full credit.

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ANSWER:

\star\bf{\:\pmb{Solution}}

\frac{4x+1}{3y²}

as, GIVEN X = 2 and y = 3

so , \frac{4(2)+1}{3(3)²}

= \frac{9}{27}

= \frac{1}{3}



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