1.

4x-5/6x+3=2x-5/3x-2​

Answer»

\huge \bold {ANSWER:-}

\huge \frac{4x - <klux>5</klux>}{<klux>6X</klux> + <klux>3</klux>} = \frac{2x - 5}{3x - 2}

then cross MULTIPLE ,

=> (4x-1)(3x+2)=(6x-5)(2x+1)

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82=>4x(3x+2)-1(3x+2)=6x(2x+1)-5(2x+1)

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82=>4x(3x+2)-1(3x+2)=6x(2x+1)-5(2x+1)=> 12x2+8x-3x-2=12x²+6x-10x-5

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82=>4x(3x+2)-1(3x+2)=6x(2x+1)-5(2x+1)=> 12x2+8x-3x-2=12x²+6x-10x-5=> 12x²+5x-2=12x²-4x-5

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82=>4x(3x+2)-1(3x+2)=6x(2x+1)-5(2x+1)=> 12x2+8x-3x-2=12x²+6x-10x-5=> 12x²+5x-2=12x²-4x-5=> 12x?+5x-12x²+4x= -5+2

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82=>4x(3x+2)-1(3x+2)=6x(2x+1)-5(2x+1)=> 12x2+8x-3x-2=12x²+6x-10x-5=> 12x²+5x-2=12x²-4x-5=> 12x?+5x-12x²+4x= -5+2=> 9x = -3

=> (4x-1)(3x+2)=(6x-5)(2x+1)Math5 points4G82=>4x(3x+2)-1(3x+2)=6x(2x+1)-5(2x+1)=> 12x2+8x-3x-2=12x²+6x-10x-5=> 12x²+5x-2=12x²-4x-5=> 12x?+5x-12x²+4x= -5+2=> 9x = -3=> x = (-3)/9


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