4xx10^(-2) moles of a non-volatile solute is added into 10 moles of solvent.The solute plymerises into soluble solid following first order kinetics with rate constant equal to 0.693 min^(-1). If after 2 min, elevation in boiling point is observed to be 0.01^(@) then calculate which form the solute is getting polymerised into? Given : Molar mass of solvent=100 g//mole. K_(b) of solvent =0.5 K-kg mol^(-1) [Instruction : Mark 2 if polymer is dimer, 3 if trimer and so on.]

4xx10^(-2) moles of a non-volatile solute is added into 10 moles of so

1.	4xx10^(-2) moles of a non-volatile solute is added into 10 moles of solvent.The solute plymerises into soluble solid following first order kinetics with rate constant equal to 0.693 min^(-1). If after 2 min, elevation in boiling point is observed to be 0.01^(@) then calculate which form the solute is getting polymerised into? Given : Molar mass of solvent=100 g//mole. K_(b) of solvent =0.5 K-kg mol^(-1) [Instruction : Mark 2 if polymer is dimer, 3 if trimer and so on.]
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