5+3√3÷7+4√3=a+b√3help please

1.	5+3√3÷7+4√3=a+b√3help please
Answer» Answer: The answer is SIMPLE yaar!!! LHS = (5 + 2√3 ) / ( 7 + 4√3 ) rationalize the denominator = (5 + 2√3 ) ( 7 - 4√3 ) / [ ( 7 + 4√3 ) ( 7 - 4√3 ) = [ 5 ×7 - 5 × 4√3 + 2√3 × 7 - 2√3 × 4√3 ] / [ (7 )² - (4√3 )² ] here we used ( x + y ) (x - y ) = x² - y² identity = [35 -20√3 + 14√3 -24 ] / [ 49 - 48 ] = (11 - 6√3 ) therefore , LHS = RHS 11 - 6√3 = A - B√3 comparing both sides A = 11, B = 6 i hope this is useful to you. Mark me as Brainliest!!!

Answer»

Answer:

The answer is SIMPLE yaar!!!

LHS = (5 + 2√3 ) / ( 7 + 4√3 )

rationalize the denominator

= (5 + 2√3 ) ( 7 - 4√3 ) / [ ( 7 + 4√3 ) ( 7 - 4√3 )

= [ 5 ×7 - 5 × 4√3 + 2√3 × 7 - 2√3 × 4√3 ] / [ (7 )² - (4√3 )² ]

here we used ( x + y ) (x - y ) = x² - y² identity

= [35 -20√3 + 14√3 -24 ] / [ 49 - 48 ]

= (11 - 6√3 )

therefore ,

LHS = RHS

11 - 6√3 = A - B√3

comparing both sides

A = 11,

B = 6

i hope this is useful to you.

Mark me as Brainliest!!!

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