1.

5.39of a mixture of FeSO_(4). 7H_(2)Oand anhydrous ferricsulphaterequires80 mL of 0.125 N permangnatesolution for complete conversion to ferricsulphate. Calculate the individual weights of eachcomponentof the original mixture .

Answer»

Solution :FERRUS ulphatepresentin the mixtureto oxidisedto ferricsulphate by permagnate solution . LET the weight of ferrous sulphatebe x gram .
m.e of `FeSO_(4).7H_(2)O`= m.e of permagnate solution
` = 0.125 xx 80 = 10 `
` :. ` eq. of `FeSO_(4) . 7H_(2) O = 10/1000 ""...(EQN . 3)`
` :. ` WT . of `FeSO_(4) .7H_(2)O = eq xx eq.wt `
` = 10/1000 xx 278`
` = 2.78 g`
and wt. of `Fe_(2) (SO_(4))_(3) = (5.39 - 2.78 ) g `
` = 2.61 g `


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