1.

5.5 mg of nitrogen gas dissolves in 180 g of water at 273 K and one atm pressure due to nitrogen gas.The mole fraction of nitrogen in 180 g of water at 5 atm nitrogen pressure is approximately

Answer»

`1XX10^(-6)`
`1xx10^(-5)`
`1xx10^(-3)`
`1xx10^(-4)`

Solution :Solubility of a gas `PROP` mole fraction
`n_(N_(2))=(5.5xx10^(-3))/(28)=1.96xx10^(-4)` at 1 atm
Now,p `prop` mole fraction
then at 5 atm, the mole fraction will increase 5 TIMES.
HENCE, `5xx1.96xx10^(-4)= 9.8xx10^(-4)~~10xx10^(-4)= 1.0xx10^(-3)`


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