1.

5.6 litre of helium gas at STP is adiabatically compressed to 0.7 litre. Taking the initial temperature to be T_(1), the work done in the process is

Answer»

`(9)/(8)RT_(1)`
`(3)/(2) RT_(1)`
`(15)/(8)RT_(1)`
`(9)/(2) RT_(1)`

Solution :`TV^(gamma-1)=C`
`T_(1)(5.6)^(2//3)=T_(2)(0.7)^(2//3) rArr T_(2)=T_(1)(8)^(2//3)=4T_(1)`
`THEREFORE Delta W` (WORK done on the SYSTEM) `=(NR Delta T)/(gamma-1) =(9)/(8) RT_(1)`


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