1.

5.85 g NaCl is dissovled in 1L water. The number of ions of Na^(+) and Cl^(-) in 1 mL of this solution will be:

Answer»

`6.02xx10^(19)`
`1.2xx10^(22)`
`1.2xx10^(20)`
`6.02xx10^(20)`

Solution :Number of MOLES of NaCl
`=("Mass")/("MOLAR mass")=(5.95)/(58.5)=0.1`
Number of ions `(Na^(+)+Cl^(-))` in 1L
`=2xx01xx6.023xx10^(23)`
`=12.046xx10^(22)`
Number of ions in 1mL `=(12.046xx10^(22))/(1000)=1.2xx10^(20)`


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