1.

5.85 g of NaCI is dissoloved in water and the solution is made upto 0.5 litre. The molarity of solution is:

Answer»

1 M
2 M
0.1 M `BaCI_(2)`
0.2 M

Solution :`"Molarity of solution (M)"=("Mass of NaCI/Molar Mass")/("Volume of solutin in liters")`
` =((5.85g)//(58.5g MOL^(-1)))/((0.5 L))`
`=((0.1 mol))/((0.5 L))=0.2 mol L^(-1)=0.2 M`


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