1.

5.85 g of NaCl are dissolved in 90 g of water, the mole fraction of NaCl is :

Answer»

0.1
0.01
0.2
0.0196

Solution :Moles of NACL`=(5.85)/(58.5)=0.1`
Moles of water `=(90)/(18)=5`
MOLE fraction of NaCl `=(0.1)/(5+0.1)=0.0196`


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