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5 A 50 mH inductor is in series with a 10 2 resistor and a battery with an emf oj 25 V. At t = 0 the switch is closed. Find Q(d) the power dissipated in the resistor

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SOLUTION : The POWER dissipated in the RESISTOR is `P_(R) = I^(2)R = I_(0)^(2)R (1 - 2e^(-t/zeta)" +e^(-2t/zeta)`


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