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5. A can do a piece of work in 40 days. He works at it for 8 days and then B finishes the remaining work. How long will A require to finish the workremaining work in 16 days. How long will they take to complete the work if they doit together?​

Answer»

s time, let's assume the work is of eating chocolates.Assume the total number of chocolates be 80 (L.C.M of 40, 8, 16)Condition 1: X eats 80 chocolates in 40 days.Hence efficiency of X is : 2 chocos / dayCondition 2: X work for 8 days. Then Y work for 16 DAYSTHE number of chocolates eaten by X in 8 days : 2*8 = 16Rest of the chocolates are eaten by Y in 16 days.Chocolates left= 80-16= 64So Y eats 64 chocolates in 16 days.Hence efficiency of Y is : 4 chocos / dayIf they work TOGETHER , Total Efficiency would be (2 chocos / day+4 chocos / day)= 6 chocos / dayNo of days they take together to finish 80 chocolates : (80/6):13 Days 8 Hours



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