Answer:

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Step-by-step explanation:

(i) inner curved surface

According to the QUESTION inner diameter is 4 cm,

then,

Inner radius of a cylindrical pipe =r  1  

=  2

innnerdiameter  

=(  24)cm=2cm

Height (H) of cylindrical pipe=77 cm,

Curved Surface Area of inner surface of pipe  =2πr  1H

=(2×  722×2×77)cm  2

=968cm  2

(ii) Outer curved surface area

According to the question outer diameter is 4.4 cm

Outer radius of cylindrical pipe =r  2  

=  2

outerdiamterer​  

=(  24.4  )cm=2.2cm

Height of cylinder = h = 77 cm,

Curved area of outer surface of pipe = 2πr  2h

=(2×  722  ×2.2×77)cm  2

=(2×22×2.2×11)cm  2

=1064.8cm 2

(iii) Total surface area

Total surface area = curved surface area of inner cylinder + curved surface of outer cylinder + 2 × Area of base

Area of base = area of circle with radius 2.2 cm - Area of circle with radius 2 cm

=πr  22−πr  12

=  722×((2.2)  2

−(2.)  2)

=  722×(4.84−4)

=  722×(0.84)

=2.74cm  2

Total surface area = curved surface area of inner cylinder + curved surface area of outer cylinder + 2 × Area of base

=968+1064.8+2×2.74

= 2032.8 + 5.76

=2039.08cm  2

Therefore, the total surface area of the cylindrical pipe is  

=2039.08cm  2