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5. A shopkeeper buys an article for 300. He increases its price by 20% and then gives 10% discount on the new price.Find : (i) the new price (marked price) of the article.(ii) the discount given by the shopkeeper.(iii) the selling price.(iv) the profit percent made by the shopkeeper. |
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Answer» 8%Step-by-step explanation:CP of an article = Rs. 300Increase in price = 20%(i) Marked price (MP)=\frac{CP(100+increase\%)}{100}= 100CP(100+increase%) =\frac{300\left(100+20\right)}{100}= 100300(100+20) =\frac{300\times120}{100}= 100300×120 = Rs. 360(II) Rate of discount = 10%AMOUNT of discount = \frac{360\times10}{100}=Rs.36 100360×10 =Rs.36(iii) Selling price = MP - discount= 360 - 36 = Rs. 324(iv) Net profit to the SHOPKEEPER= SP - CP = Rs. 324 - Rs. 300 = Rs. 24Gain% = \frac{Gain\times100}{CP}=\frac{24\times100}{300}=8\% CPGain×100 = 30024×100 =8% |
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