5. Calculate the weight of 3.491 x 1019 molecules of Cl2.1101 1022ubot – InterviewSolution

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5. Calculate the weight of 3.491 x 1019 molecules of Cl2.1101 1022ubotic the ato

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there are n no molecules of cl2. no of moles of cl2 are n/(6.023×10*23)therefore mass is moles × 71n ×71/(6.023×10*23)0.848 ×10*23

0.000058 is the correct ans

0.58*20^-4 is the correct answer

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