InterviewSolution
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InterviewSolution
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`5`g of steam at `100^(@)C` is mixed with `10`g of ice at `0^(@)C`. Choose correct alternative /s) :- (Given `s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g`)A. Equilibrium temperature of mixture is `160^(@)C`B. Equilibrium temperature of mixture is `100^(@)C`C. At equilibrium ,mixture contains `13(1)/(3)g` of waterD. At equilibrium ,mixture contains `1(2)/(3) kg` of steam |
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Answer» Correct Answer - B::C::D Required heat `" "` Available heat `10`g ice (`0^(@)C`) `" "` `5` of steam (`100^(@)C`) `darr800"cal"` `" "` `darr2700"cal"` `10` g of water (`0^(@)C`) `" "` `5` g water(`100^(@)C`) `darr1000"cal"` `10` g water (`100^(@)`) So available heat is more than required heat therefore final temperature will be `100^(@)C`. Mass of vapour condensed =`(800+1000)/(540) = (10)/(3)g` Total mass of water =`10 + (10)/(3) = (40)/(3) = 13(1)/(3)`g Total mass of steam = ` 5 - (10)/(3) = (5)/(3) = 1(2)/(3)`g |
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