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5 g sample contain only Na_(2)CO_(3)and Na_(2)SO_(4)This sample is dissolved and the volume made up to 500 mL. 25 mL of this solution neutralizes 20 mL of 0.1 M H_(2)SO_(4). Calculate the percentage of Na_(2)SO_(4) in the sample. |
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Answer» `Na_(2)CO_(3) + H_(2)SO_(4) to Na_(2)SO_(4) + H_(2)CO_(3)` = `20 XX 0.1 =2` no. Of moles of `Na_(2)CO_(3)` in 500 ML solution `=500/25 xx 2= 40` wt. Fo `Na_(2)CO_(3) = 40 xx 106 xx 10^(-3) = 4.24`G = 84.8 |
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