1.

5 gm of CaCO_(3) is made to react with 0.2M, 100ml HCl solution. What will be the volumes of CO_(2)gas evolved at NTP?

Answer»

2240ml
224ml
22.4L
224L

Solution :LR
`CaCO_(3)+ 2HClrarrCaCl_(2)+H_(2)O+CO_(2)`
mole `(5)/(10)=0.05 (0.2xx100)/(1000)=0.02`
`n_(CO_(2))` produce `=(n_(HCl))/(2)=(0.02)/(2)=0.01`
`V_(CO_(2))NTP=22.4xx0.01` LITRE
`=22400xx0.01ml`
=224'ml


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