1.

5.How much heat is required to change 10g ice at 0°C to steam at 100°C? Latent heat of fusionand vapourisation for H2O are 80 callg and 540 cal/g respectively. Specific heat of water is 1cal/g.

Answer»

Q=mL+mcΔt+mL'

=10*80+10*1*(100-0)+10*540

=800+1000+5400

=7200cal.=7.2kcal

L=heat of fusion of ice

L'=heat of vapourisation of water



Discussion

No Comment Found