5 MARKS THEORY QUESTIONS1)Explain ohm's law applied to complete circui

1.	5 MARKS THEORY QUESTIONS1)Explain ohm's law applied to complete circuit.A conductor having diameter 0.4 mm has resistivity 5 x 10-7 Ωm and its length is 10.05 m. What isthe resistance of conductor?(R = 40Ω)
Answer» Ohm'slawstates that the current through aconductorbetween two points is directly proportional to the voltage across the two points. Thislawis one of the most basiclawsof electricity. It helps to calculate power, efficiency, current, voltage, and resistance of an element of an electricalcircuit. Resistance is given by: R=ρL/A ρ=resistivity L=length of the conductor(in m) A=area of cross section of the conductor (in m2) diameter is 0.4mm=0.4×10^-3m Area =πd^2/4=1.25×10^-7m2 ρ=RA/L=2.5×1.25×10^-7/1.2=2.6×10^-7ohm m

5 MARKS THEORY QUESTIONS1)Explain ohm's law applied to complete circuit.A conductor having diameter 0.4 mm has resistivity 5 x 10-7 Ωm and its length is 10.05 m. What isthe resistance of conductor?(R = 40Ω)

Answer»

Ohm'slawstates that the current through aconductorbetween two points is directly proportional to the voltage across the two points. Thislawis one of the most basiclawsof electricity. It helps to calculate power, efficiency, current, voltage, and resistance of an element of an electricalcircuit.

Resistance is given by:

R=ρL/A

ρ=resistivity

L=length of the conductor(in m)

A=area of cross section of the conductor (in m2)

diameter is 0.4mm=0.4×10^-3m

Area =πd^2/4=1.25×10^-7m2

ρ=RA/L=2.5×1.25×10^-7/1.2=2.6×10^-7ohm m

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