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5 mL of 0.4N NaOH is mixed with 20 mL of 0.1N HCl. The pH of the resulting solution will be : |
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Answer» 6 Moles of `NaOH=(0.4)/(1000)xx5=2xx10^(-3)` moles Moles of `HCl = (0.1)/(1000)xx20=2xx10^(-3)` moles As the moles of NaOH and HCl are EQUAL, the resulting solution will be NEUTRAL. |
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